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9.

For a normal distribution with mean 20 and standard deviation 5, approximately what percent of
the observations will be between 5 and 35?
A. 50%
B. 68%
C. 95%
D. 99.7%

User Fered
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1 Answer

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Answer: D. 99.7%

Explanation:

Scores that lies within the first deviation(1σ) =

(20 - 5) to (20 + 5) → 15 to 25

Scores that lies within the second deviation(2σ) =

(20 - 5 - 5) to (20 + 5 + 5) → 10 to 30

Scores that lies within the third deviation(3σ) =

(20 - 5 - 5 - 5) to (20 + 5 + 5 + 5) → 5 to 35

As shown by the distribution graph below, 99.73% of the scores lies within the third deviation(3σ).

9. For a normal distribution with mean 20 and standard deviation 5, approximately-example-1
User Wjk
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