We are required to find the distance between both chords.
Answer:
17 cm
Explanation:
The two chords are parallel to each other.
This means that a perpendicular line drawn from the centre of the circle will divide both of them into 2 equal sides.
This is depicted in the image attached.
From the Image,the diagonal drawn from one end of either chord through the centre will form the hypotenuse side of either chords.
Thus, using pythagoras theorem, we have for the chord that has a length of 10 cm. Perpendicular distance from centre of chord to centre of circle is;
d = √(13² - 5²)
d = √144
d = 12
Similarly, for chord with length = 24 cm, we have;
d' = √(13² - 12²)
d' = √25
d' = 5
Therefore, distance between chords = d + d' = 12 + 5 = 17 cm