Question

Calculate the molarity of 198 g of barium iodide (Bal2) in 2.0 l of solution

Answer 1

Answer: The molarity of 198 g of barium iodide
`(BaI_(2))` in 2.0 L of solution is 0.253 M.

Step-by-step explanation:

Given: Mass = 198 g

Volume = 2.0 L

Molarity is the number of moles of solute present in liter of a solution.

Moles is the mass of a substance divided by its molar mass. So, moles of barium iodide (molar mass = 391.136 g/mol) is calculated as follows.

`Moles = (mass)/(molar mass)\\= (198 g)/(391.136 g/mol)\\= 0.506 mol`

Now, molarity is calculated as follows.

`Molarity = (moles)/(Volume (in L))\\= (0.506 mol)/(2.0 L)\\= 0.253 M`

Thus, we can conclude that the molarity of 198 g of barium iodide
`(BaI_(2))` in 2.0 L of solution is 0.253 M.