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Find four consecutive integers with the sum of 2021

User Amras
by
4.6k points

1 Answer

3 votes

Answer:

This problem has not solution

Explanation:

lets the integers be:

x

x+1

x+2

x+3

so:

x+(x+1)+(x+2)+(x+3)=2021

x+x+x+x+1+2+3=2021

4x+6=2021

4x=2021-6=2015

x=2015/4=503.75

x is not a integer

User GDY
by
4.4k points