Question

Thanks to whoever decides to help

Answer 1

`\displaystyle\ S=Vt=> V=(S)/(t )` in our case, S is d(h) ; and t is t (x), then
`\displaystyle\ V=(d(x))/(t(h))=\bigg((d)/(t) \bigg )(h)=(6h^2-h-1)/(2h-1) =(2h^2-h+4h^2-1)/(2h-1) =\\\\\\\\\frac{h\underline{(2h-1)}+\underline{(2h-1)}(2h+1)}{2h-1} =((3h+1)(2h-1))/(2h-1) =\boxed{3h+1}\\\\\\Answer: \boxed{V=3h+1}`