Question

In a double-slit experiment, the slit spacing is 0.120 mm and the screen is 2.00 m from the slits. Find the wavelength (in nm) if the distance between the central bright region and the third bright fringe on a screen is 2.75 cm.

Answer 1

`\lambda=550nm`

Step-by-step explanation:

From the question we are told that:

The slit spacing
`d_s=0.120mm=>0.120*10^(-3)`

Screen distance
`d_(sc)=2.0m`

Third Distance
`X=2.75cm=>2.75*10^(-2)`

Generally the equation for Wavelength is mathematically given by

`\lambda=(Xd_s)/(n*d_(sc))`

Where

n=number of screens

`n=3`

Therefore

`\lambda=(2.75*10^(-2)*0.120*10^(-3))/(3*2)`

`\lambda=0.055*10^(-5)`

`\lambda=550nm`