Question

A 2.90 m segment of wire supplying current to the motor of a submerged submarine carries 1400 A and feels a 2.00 N repulsive force from a parallel wire 4.50 cm away. What is the direction and magnitude (in A) of the current in the other wire? magnitude A direction

Answer 1

`I_2=30.9A`

Step-by-step explanation:

From the question we are told that:

Wire segment
`l_s=2.9m`

Initial Current
`I_1=1400A`

Force
`F=2.00N`

Distance of Wire
`d=4.50cm=>0.0450m`

Generally the equation for Force is mathematically given by

`F=(\mu_0 * I_1*I_2*l_s)/(2 \pi *r)`

`F=(4 \pi*10^(-7) *1400 I*I_2*2.9)/(2 \pi *0.0450)`

`I_2=(22.5*10^-2)/(2*10^(-7)*1400*2.6)`

`I_2=30.9A`