Question

1. A 225-L barrel of white wine has an initial free SO2 concentration of 22 ppm and a pH of 3.70. How much SO2 (in grams) should be added to the barrel to result in the required SO2 level

Answer 1

The appropriate answer is "9.225 g".

Step-by-step explanation:

Given:

Required level,

= 63 ppm

Initial concentration,

= 22 ppm

Now,

The amount of free SO₂ will be:

=
`Required \ level -Initial \ concentration`

=
`63-22`

=
`41 \ ppm`

The amount of free SO₂ to be added will be:

=
`41* 225`

=
`9225 \ mg`

∵ 1000 mg = 1 g

So,

=
`9225* (1)/(1000)`

=
`9.225`

Thus,

"9.225 g" should be added.