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( t^15/27x^9 ) ^-2/3

Please solve this
it is fraction with a negative fraction exponent

User Anbusekar
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1 Answer

4 votes

Answer:

Explanation:

Exponent laws:


(a^(m))^(n)=a^(m*n)\\\\a^(-m)=(1)/(a^(m))


(t^{(15)/(27)}x^(9)})^{(-2)/(3)}= \ t^{(15)/(27)*(-2)/(3)}*x^{9*(-2)/(3)}\\\\\\= t^{(5)/(9)*(-2)/(3)}*x^(3*-2)\\\\=t^{(-10)/(27)}x^(-6)\\\\=\frac{1}{t^{(10)/(27)}x^(6)}

User Surfer
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