Question

A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.601 mol of a gaseous product. If the cylinder contained 0.300 mol of gas before the reaction and had an initial volume of 2.16 L, what was its volume after the reaction

Answer 1

4.33 L

Step-by-step explanation:

Assuming ideal behaviour and that all 0.300 moles of gas reacted, we can solve this problem using Avogadro's law, which states that at constant temperature and pressure:

• V₁n₂ = V₂n₁

Where in this case:

• V₁ = 2.16 L

• n₂ = 0.601 mol

• V₂ = ?

• n₁ = 0.300 mol

We input the given data:

• 2.16 L * 0.601 mol = V₂ * 0.300 mol

And solve for V₂:

• V₂ = 4.33 L