Question

A 1m3 tank containing air at 25℃ and 500kPa is connected through a valve to

another tank containing 5kg of air at 35℃ and 200kPa. Now the valve is opened,
and the entire system is allowed to reach thermal equilibrium, which is at 20℃
(Take: Ru = 8.314 kJ / kg.K).

Answer 1

The right answer is "2.2099 m³".

Step-by-step explanation:

Given:

Mass,

m = 5 kg

Temperature,

T = 35℃

or,

= 35 + 273

Pressure,

P = 200 kPa

Gas constant,

R = 0.2870 kj/kgK

By using the ideal gas equation,

The volume will be:

⇒
`PV=mRT`

or,

⇒
`V=(mRT)/(P)`

By substituting the values, we get

`=(5(0.2870)(35+273))/(200)`

`=(441.98)/(200)`

`=2.2099 \ m^3`