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Determine the 2nd and 3rd terms of a geometric sequence of which T1 =5 and T4=40​

Determine the 2nd and 3rd terms of a geometric sequence of which T1 =5 and T4=40​-example-1
User Dreta
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1 Answer

3 votes

Answer:

Second term of this sequence:
10.

Third term of this sequence:
20.

Explanation:

The first step is to find the common ratio of this sequence.

In a geometric sequence, multiply one term by the common ratio to find an expression for the next term. Let
r denote the common ratio of this sequence. For this sequence:

  • The first term of this sequence is
    5.
  • Multiply the first term by the common ratio to find an expression for the third term:
    5\, r.
  • Multiply the second term by the common ratio to find an expression for the fourth term:
    5\, r^(2).
  • Similarly, an expression for the the fourth term would be:
    5\, r^(3).

However, the question states that the value of the fourth term is
40. In other words,
5\, r^(3) = 40.

Solve this equation for
r:


r^(3) = 8.


r = 2.

(Since the power of
r is non-even in the equation, there's no need to consider the sign of
r\! when taking the cube root.)

Substitute
r = 2 into the expression for the second term and the third term to find their values:

  • Second term:
    5\, r = 10.
  • Third term:
    5\, r^(2) = 20.
User Kwhitley
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