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y = x {}^(2) - 9x + 14

Given that y can be written in the form

(x + a) {}^(2) + b
, where a and b are constants, find the value of a and the value of b.​
pls help i rly need this Pls pls pls pls

User Jouhar
by
7.7k points

2 Answers

4 votes

Answer:

a = 4.5

b = -6.25

Explanation:

The given equation to us is ,


\implies y = x {}^(2) - 9x + 14

And its given that it can we written in the form of ,


\implies (x + a) {}^(2) + b

Where ,

  • a and b are constants .

Therefore ,


\implies y = x^2 -9x + 14

Multiplying 9x by 2/2 ,we have ,


\implies y = x^2 -(2)/(2)* 9 x + 14

Adding and subtracting (9/2)² ,


\implies y = \bigg\{ x^2 -(2)/(2)* 9 x + \bigg((9)/(2)\bigg)^2 \bigg\} +14 -\bigg((9)/(2)\bigg)^2

Therefore , we can write it as ,


\implies y = \bigg( x + (9)/(2)\bigg)^2 + 14 - 20.25 \\\\\implies \underline{\underline{ y = \bigg( x + (9)/(2)\bigg)^2 - 6.25 }}

Hence the value of a is 9/2 and b is -6.25 .

User Laurapons
by
8.3k points
4 votes

Answer:

a = -
(9)/(2) , b = -
(25)/(4)

Explanation:

To obtain the required form use the method of completing the square

add/ subtract ( half the coefficient of the x- term)² to x² - 9x

y = x² + 2(-
(9)/(2) )x +
(81)/(4) -
(81)/(4) + 14

= (x -
(9)/(2) )² -
(81)/(4) +
(56)/(4)

= (x -
(9)/(2) )²-
(25)/(4) ← in the form (x + a)² + b

with a = -
(9)/(2) and b = -
(25)/(4)

User Keybee
by
8.7k points

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