Question

PLEASE HELP ME WITH THIS ONE QUESTION

A photon has 2.90 eV of energy. What is the photon’s wavelength? (h = 6.626 x 10^-19, 1 eV = 1.6 x 10^-19 J)

Answer 1

Step-by-step explanation:

First, we convert the energy from eV to Joules:

`2.90\:\text{eV}×\left(\frac{1.6×10{-19}\:J}{1\:\text{eV}} \right)`

`= 4.64×10^(-19)\:\text{eV}`

We know from definition that

`E=h\\u = (hc)/(\lambda)`

so the wavelength of the photon is

`\lambda = (hc)/(E) = 4.28×10^8\:\text{m}`