If x = 3 and y = 2, then the value of ( x - y )(x² + xy + y²) is (a) 31 (b) 19 (c) 1 (d) 25

asked Apr 4, 2022 206k views

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If x = 3 and y = 2, then the value of ( x - y )(x² + xy + y²) is

(a) 31 (b) 19 (c) 1 (d) 25

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$\displaystyle\bf \underbrace{ (x-y)(x^2+xy+y^2)}}_(x^3-y^3)=3^3-2^3=19\\\\Answer: b)19$

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4 votes

Answer:

Explanation:

(3-2)(3^2+3x2+2^2)

(1)(9+6+4)

(1)(19)

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