Question

The figure is made up of a cylinder and a cone.

What is the exact volume of the figure?

Answer 1

`\displaystyle\bf \boxed{ V_(cylinder)=\pi r^2h \ ; \ \ V_(cone)=(1)/(3) \cdot \pi r^2h} \\\\\\V_0=V_(cylinder)+V_(cone)=? \\\\V_0=(1)/(3) \cdot 3^2\cdot 5\pi +3^2\cdot4\pi =15\pi +36\pi =\boxed{51\pi \ ft^3}`

Answer 2

52π

Explanation:

Volume of the cone, 5×3²×π/3 = 15π

Volume of the Cylinder, π×3²×4=36π

Adding them, 15π+36π=51π

Answered by GAUTHMATH