Question

Its

A bag contains 5 green candies and 7 blue candies.
A piece of candy is selected at random, put back into the bag, and then
another piece of candy is chosen.
What is the probability that both pieces are green?

Answer 1

`P(Green\ and\ Green) = (25)/(144)`

Explanation:

Given

`Green=5`

`Blue = 7`

Required

`P(Green\ and\ Green)`

This is calculated as:

`P(Green\ and\ Green) = P(Green) * P(Green)`

Since, it is a probability with replacement, we have:

`P(Green\ and\ Green) = (Green)/(Total) * (Green)/(Total)`

So, we have:

`P(Green\ and\ Green) = (5)/(12) * (5)/(12)`

`P(Green\ and\ Green) = (25)/(144)`