Question

A child who is swimming toward shore at 0.78 m/s sees shark and picks up his speed

to 1.89 m/s. He covers 17.5 m until he lands on shore. What was his acceleration?

Answer 1

0.085m/s²

Step-by-step explanation:

Use v²=v0²+2a(d)

solve for a

v²-v0²/2d=a

Plug in givens

1.89²-0.78²/2*17.5=a

Plug into calculator

a=0.085m/s²