Question

How many grams of ammonia can be produced from reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm?

Answer 1

Answer: The mass of ammonia is 124457.96 g which can be produced from reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

Step-by-step explanation:

Given: Volume = 450 L

Temperature = 450 K

Pressure = 300 atm

The reaction equation is as follows.

`N_(2) + 3H_(2) \rightarrow 2NH_(3)`

Here, 1 mole of nitrogen reacts to give 2 moles of ammonia.

From the given data, moles of nitrogen are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows.

`PV = nRT\\300 atm * 450 L = n * 0.0821 L atm/mol K * 450 K\\n = (300 atm * 450 L)/(0.0821 L atm/mol K * 450 K)\\= (135000)/(36.945)\\= 3654.08 mol`

For 3654.08 moles of nitrogen, the moles of ammonia produced is as follows.

`2 * 3654.08 mol\\= 7308.16 mol`

Therefore, mass of ammonia (molar mass = 17.03 g/mol) is calculated as follows.

`Moles = (mass)/(molarmass)\\7308.16 mol = (mass)/(17.03 g/mol)\\mass = 124457.96 g`

Thus, we can conclude that the mass of ammonia is 124457.96 g which can be produced from reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.