Question

How many liters of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K?

Answer 1

Answer: A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

Step-by-step explanation:

Given: Mass of Mg = 2.3 g

Pressure = 2 atm

Temperature = 298 K

The reaction equation is as follows.

`Mg + 2HCl \rightarrow MgCl_(2) + H_(2)`

This shows that 1 mole of Mg gives 1 mole of
`H_(2)`.

Hence, moles of Mg for the given mass is calculated as follows.

`Moles = (mass)/(molar mass)\\= (2.3 g)/(24.30 g/mol)\\= 0.095 mol`

Hence, 0.095 moles of Mg will give 0.095 moles of
`H_(2)`.

Formula used to calculate volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows.

`PV = nRT\\2 atm * V = 0.095 mol * 0.0821 L atm/mol K * 298 K\\V = (0.095 mol * 0.0821 L atm/mol K * 298 K)/(2 atm)\\= 1.16 L`

Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.