Question

I got c which is 100 but I don’t know how jerry got A

Answer 1

Choice C is the correct answer because

`((6+2)^3-12)/(5)\\\\((8)^3-12)/(5)\\\\(512-12)/(5)\\\\(500)/(5)\\\\100\\\\`

So in short,
`((6+2)^3-12)/(5)=100\\\\`

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The mistake Jerry likely made was that he only cubed the 2 and didn't realize the 6 was part of that cubing process. It seems he didn't add first and decided to cube before adding.

This is probably what steps Jerry did

`(6+2^3-12)/(5)\\\\(6+8-12)/(5)\\\\(14-12)/(5)\\\\(2)/(5)\\\\`

But as mentioned, those steps are incorrect because the 6 is part of the cubing operation. In other words, Jerry should have added the 6+2 first before cubing afterward (due to PEMDAS determining the order of operations).

Or you could think of it like this

`((6+2)^3-12)/(5)\\\\((6+2)(6+2)(6+2)-12)/(5)\\\\((8)(8)(8)-12)/(5)\\\\(512-12)/(5)\\\\(500)/(5)\\\\100`