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Question 1
1 pts
How many mols of bromine are present in 35.7g of
Tin(IV) bromate?

User Aaront
by
4.4k points

1 Answer

7 votes

Answer:

n = 0.0814 mol

Step-by-step explanation:

Given mass, m = 35.7g

The molar mass of Tin(IV) bromate, M = 438.33 g/mol

We need to find the number of moles of bromine. We know that,

No. of moles = given mass/molar mass

So,


n=(35.7)/(438.33)\\\\n=0.0814\ mol

So, there are 0.0814 moles of bromine in 35.7g of Tin(IV) bromate.

User Kevin Rave
by
4.2k points