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Find the points of intersection of the graphs involving the following pair of functions.

f(x)=2x^2 + 3x - 3 and g(x) = -x^2

User NealR
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1 Answer

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Answer:


{ \tt{f(x) = 2 {x}^(2) + 3x - 3 }} \\ { \tt{g(x) = - {x}^(2) }} \\ f(x) + 2 * g(x) : \\ 0 {x}^(2) + 3x - 3 = 0 \\ x = 1

point's (1, 0)

User William Gu
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