Answer:
The correct answer is -
a. incomplete dominance
b. f2 = 1:2:1 = straight:wavy:curly
Step-by-step explanation:
In this question, it is given that a person with curly hair and a person with straight hair has all children with wavy hair. It means that the heterozygous offspring in F1 has blended traits which means this trait shows incomplete dominance. Suppose C is curly hair c is straight hair then f1 offspring will have Cc (wavy hair)
now in F2:
cross: Cc cross with Cc
gametes: C, c
Punnett square:
C c
C CC Cc
c Cc cc
Thus, the genotype and phenotype ration would be :
genotype: 1:2:1 = CC:Cc:cc
phenotype: 1:2:1 = straight:wavy:curly