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Please help ASAP !!! Thank you !
asked
Nov 17, 2022
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Please help ASAP !!! Thank you !
Mathematics
college
Joel Kennedy
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Joel Kennedy
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(1)
=(a+b)(3c-d)
=a(3c-d)+b(3c-d)
=3ac-ad+3bc-bd
(2)
=(a-b)(c+2d)
=a(c+2d)-b(c+2d)
=ac+2ad-bc-2bd
(3)
=(a-b)(c-2d)
=a(c-2d)-b(c-2d)
=ac-2ad-bc+2bd
(4)
=(2a+b)(c-3d)
=2a(c-3d)+b(c-3d)
=2ac-6ad+bc-3bd
Ben Strombeck
answered
Nov 23, 2022
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Ben Strombeck
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