Question

Calculate the osmotic pressure of 5.0g of sucrose ssolution in 1L. Answer should be in Torr

Answer 1

Answer: The osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.

Step-by-step explanation:

Given: Mass = 5.0 g

Volume = 1 L

Molar mass of sucrose = 342.3 g/mol

Moles are the mass of a substance divided by its molar mass. So, moles of sucrose are calculated as follows.

`Moles = (mass)/(molarmass)\\= (5.0 g)/(342.3 g/mol)\\= 0.0146 mol`

Hence, concentration of sucrose is calculated as follows.

`Concentration = (moles)/(Volume (in L))\\= (0.0146 mol)/(1 L)\\= 0.0146 M`

Formula used to calculate osmotic pressure is as follows.

`\pi = CRT`

where,

`\pi` = osmotic pressure

C = concentration

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

`\pi = CRT\\= 0.0146 * 0.0821 L atm/mol K * 298 K\\= 0.357 atm (1 atm = 760 torr)\\= 271.32 torr`

Thus, we can conclude that the osmotic pressure of 5.0g of sucrose solution in 1 L is 271.32 torr.