Given:
of a number is added to
it gives the same result as taking
of the number from
.
To find:
The unknown number.
Solution:
Let x be the unknown number.
of a number is added to
it gives the same result as taking
of the number from
.
![(5)/(4)+(3)/(4)x=20(1)/(3)-(7)/(8)x](https://img.qammunity.org/2022/formulas/mathematics/high-school/gdnzdeuvcpdw9mtmlti0n0r8h6uoe0x7yq.png)
![(5+3x)/(4)=(61)/(3)-(7)/(8)x](https://img.qammunity.org/2022/formulas/mathematics/high-school/g2uglaxopjyetrrr2vvguq6rr7ltekce0g.png)
![(5+3x)/(4)=(488-21x)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3xuelufqqd1tyjnh1h1agyrxffnzeqnm1w.png)
Multiply both sides by 24.
![6(5+3x)=488-21x](https://img.qammunity.org/2022/formulas/mathematics/high-school/xga7sxtb4hpski1nmzrxh8zs4tr7yj6dpw.png)
![30+18x=488-21x](https://img.qammunity.org/2022/formulas/mathematics/high-school/9g7lkdn08dowg6i6pdn8fy45ve7kl7eh51.png)
![18x+21x=488-30](https://img.qammunity.org/2022/formulas/mathematics/high-school/aaf4aen8m5g2vfcsa0zgwu163q16r9stvj.png)
![39x=458](https://img.qammunity.org/2022/formulas/mathematics/high-school/vdiwxep5sagq18jmw6smac1goxzeii2vjk.png)
Divide both sides by 39.
![x=(458)/(39)](https://img.qammunity.org/2022/formulas/mathematics/high-school/sku6ydord7casklb1tn26sg3oiveyu2dlw.png)
Therefore, the required number is
.