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Can anyone answer this? (2y²-3xy)÷y.​

User Xys
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1 Answer

1 vote

Answer:

2y - 3x

Explanation:

Given

(2y² - 3xy) ÷ y

Divide each term on the numerator by y , that is


(2y^2)/(y) -
(3xy)/(y) ( cancel y on numerator/ denominator of both fractions )

= 2y - 3x

User Gergely Szilagyi
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5.5k points