Question

If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) in terms of n?

Answer 1

t(d(n)) = 12n + 7

Explanation:

• t(d) = 3d + 1
• d(n) = 4n + 2

t(d(n)) = t(4n + 2)

Substitute the function d(n) into the function t(d) for the variable d.

t(4n + 2) = 3(4n + 2) + 1

• 12n + 6 + 1
• 12n + 7

t(d(n)) = 12n + 7