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\frac{(1)/(a+1) }{a-\frac{1}{{a+(1)/(a)}{} } } someone help please

User BeeNag
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Hello,


a\\eq 0\\\\((1)/(a+1) )/(a-(1)/(a+(1)/(a) )) \\\\\\=\frac{(1)/(a+1)}{\frac{a(a^2+1)+a} {a^2+1} }\\\\\\=(a^2+1)/(a(a+1)(a+2))

User Zeacuss
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