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Someone please help me I’m literally struggling

Someone please help me I’m literally struggling-example-1

2 Answers

6 votes
The first question will be 3x to the power of 3
The second one will 2
The third will substitute a and put 3x and substitute b and but 2
User Erik Buchanan
by
8.4k points
6 votes

Hello,

We have :

27 = 3³ = 3 × 3 × 3


x³ =
x ×
x ×
x

So :

The cube root of 27
x³ is :

3 ×
x = 3
x

( because : (3
x)³ = 27
x³ )

We have :

8 = 2³ = 2 × 2 × 2

So :

The cube root of 8 is : 2


a^(3) +b^(3) = (a+b)(a^(2) -ab+b^(2) ) with
a=3x and
b=2

We have :


(3x)^(3)+2^(3)=(3x+2)((3x)^(2) -(3x)(2)+(2 )^(2) )

Have a nice day :)

User Jackdbd
by
8.0k points

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