Answer:
![T=8.33A](https://img.qammunity.org/2022/formulas/physics/high-school/a816o4tdogeoj8p2jjdp52dpysxflgq4r5.png)
Step-by-step explanation:
From the question we are told that:
Number of battery
![n=10](https://img.qammunity.org/2022/formulas/mathematics/high-school/ky4ds7bv3z3061jiq074l1np06q6g0x3kk.png)
Voltage source
![E=12V](https://img.qammunity.org/2022/formulas/physics/high-school/4c64sgj8p06dznq9i2c880qlh4zedbia8x.png)
Lamp Power
![P=10W](https://img.qammunity.org/2022/formulas/physics/high-school/rk6pxgoco7pj75b0an9pmwzov1yq0awwrf.png)
Generally the equation for Resistance is mathematically given by
![R=(V^2)/(P)](https://img.qammunity.org/2022/formulas/physics/high-school/t3uwz0koejgltznbz8o03fhngkahqnajhv.png)
![R=(12^2)/(10)](https://img.qammunity.org/2022/formulas/physics/high-school/l2gah6m3b64pg8mqym2i4fllspycpic5ev.png)
![R=14.4ohms](https://img.qammunity.org/2022/formulas/physics/high-school/azrzwowc2svyxrdfdgkm7mbnl1hj6ddsva.png)
Therefore
![R_(eq)=(14.4)/(10)](https://img.qammunity.org/2022/formulas/physics/high-school/cts2omcf8y4dojw3fq1muzfj9o6pimwfti.png)
![R_(eq)=1.44](https://img.qammunity.org/2022/formulas/physics/high-school/ttkdenvax0mbnjufxjqe3jqk5uop0zf4mt.png)
Generally the equation for Current is mathematically given by
![T=\ffrac{V}{Req}](https://img.qammunity.org/2022/formulas/physics/high-school/vyg0gpnnrkybmmshpfskwkc3os7u1trvbq.png)
![T=(12)/(1.44)](https://img.qammunity.org/2022/formulas/physics/high-school/expq3ckhe08dekwnpypsl0656a65vyxx18.png)
![T=8.33A](https://img.qammunity.org/2022/formulas/physics/high-school/a816o4tdogeoj8p2jjdp52dpysxflgq4r5.png)