Question

A stone is thrown with an initial speed of 12 m/s at an angle of 30o above the horizontal from the top edge of a cliff. If it takes the stone 5.6 s to reach the bottom, how far does the stone travel horizontally

Answer 1

`d=58m`

Step-by-step explanation:

From the question we are told that:

Initial Speed
`U=12m/s`

Time
`T=5.6s`

Angle
`\theta=30`

Generally the Newton's equation for motion is mathematically given by

`d=d'+ut+(at^2)/(2)`

`d=12cos30*5.6`

`d=58m`