Question

Calculate the electric field acting on the electron in a hydrogen atom due to the proton in the nucleus the radius of the orbit of the electron is 5.3×10^-11

Answer 1

`F=-8.2*10^(-8)N`

Step-by-step explanation:

From the question we are told that:

Radius
`r=5.3*10^(-11)`

Where

Proton Charge
`q_1=1.6*10^(-19)C`

Charge of Electron
`q_2=-1.6*10^(-19)C`

Generally the equation for Coulomb's Law is mathematically given by

`F=(9*10^9(q_1)(q_2))/(r^2)`

`F=(9*10^9(1.6*10^(-19)C)(-1.6*10^(-19)C))/(5.3*10^(-11))`

`F=-8.2*10^(-8)N`