Question

What volume is occupied by 0.104 mol of helium gas at a pressure of 0.91 atm and a temperature of 314 K ?

Answer 1

The volume will be "2.95 L".

Step-by-step explanation:

Given:

n = 0.104

p = 0.91 atm

T = 314 K

Now,

The Volume (V) will be:

=
`(nRT)/(P)`

By putting the values, we get

=
`(0.104* 0.0821* 314)/(0.91)`

=
`(2.6810)/(0.91)`

=
`2.95 \ L`