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If f(1) =160 and f(n+1)=-2f(n), What is f(4)?
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1 vote
If f(1) =160 and f(n+1)=-2f(n),
What is f(4)?

User Memoalv
by
3.4k points

2 Answers

5 votes

Answer:

f(n+1=-2f(n)

f(x)=-2f(n)

f(4)

f(4)=-2f(4)

User Gawbul
by
3.4k points
3 votes

Answer:

f(4) = - 1280

Explanation:

Using the recursive rule and f(1) = 60 , then

f(2) = - 2f(1) = - 2 × 160 = - 320

f(3) = - 2f(2) = - 2 × - 320 = 640

f(4) = - 2f(3) = - 2 × 640 = - 1280

User Tomgi
by
3.3k points
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