Answer:
![(7 + 7 √(5) )/( - 4)](https://img.qammunity.org/2022/formulas/mathematics/college/g7tm73cvwc4ogry9e1q4onrko4sf25ihf7.png)
Explanation:
We would multiply the fraction by its conjugate
( A conjugate is a expression that has the same integer or number values but have different signs) for example
![5x + 2](https://img.qammunity.org/2022/formulas/mathematics/college/vmthnqezis8l5kau6z87fbjab66iw0njcy.png)
and
![5x - 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/mf7dci686t737ou6p5m07iftnngeslgm8s.png)
ARE Conjugates.
The conjugate of
![1 - √(5)](https://img.qammunity.org/2022/formulas/mathematics/college/sqlx14rmdrdjtdr9guwojku0ymh6nroxc0.png)
is
![1 + √(5)](https://img.qammunity.org/2022/formulas/mathematics/college/2u5245xphv74vrr10z7rp4rsns5rv18mxc.png)
So this means we will multiply the expression by 1 plus sqr root of 5 on the numerator and denominator.
Our new numerator will be
![7 * (1 + √(5) ) = 7 + 7 √(5)](https://img.qammunity.org/2022/formulas/mathematics/college/vgqmdl3hjnxlqymh0fqy8o5h26qj10jhfd.png)
We can apply the difference of squares for the denominator.
![(x + y)(x - y) = x {}^(2) - {y}^(2)](https://img.qammunity.org/2022/formulas/mathematics/college/ouhgamu22jl5chugepd4tg4ki939s6c5f8.png)
So our denominator will be
![1 - 5 = - 4](https://img.qammunity.org/2022/formulas/mathematics/college/6eeuz57o0ke3i3jrjvt9xgaue378p0ntmi.png)
So our rationalized fraction will be
![(7 + 7 √(5) )/( - 4)](https://img.qammunity.org/2022/formulas/mathematics/college/g7tm73cvwc4ogry9e1q4onrko4sf25ihf7.png)