Solve the inequality x^3+4x>5x^2 please show steps and interval notation. thank you.

asked Aug 23, 2022 106k views

4 votes

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4 votes

Answer:
$x\in (0,1)\cup (4,\infty)$

Explanation:

Given

In equality is
x^3+4x>5x^2

Taking terms one side

$\Rightarrow x^3-5x^2+4x>0\\\Rightarrow x(x^2-5x+4)>0\\\Rightarrow x(x^2-4x-x+4)>0\\\Rightarrow x(x-4)(x-1)>0\\\Rightarrow (x-0)(x-1)(x-4)>0$

Using wavy curve method

$x\in (0,1)\cup (4,\infty)$

Faranjit answered Aug 30, 2022

8.8k points

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