Question

How long does it take to send a 15 MiB file from Host A to Host B over a circuit-switched network, assuming: Total link transmission rate

Answer 1

The answer is "102.2 milliseconds".

Step-by-step explanation:

Given:

Size of file = 15 MiB

The transmission rate of the total link= 49.7 Gbps

User = 7

Time of setup = 84.5 ms

calculation:

`1\ MiB = 2^(20) = 1048576\ bytes\\\\1\ MiB = 2^(20 * 8)= 8388608\ bits\\\\15\ MiB= 8388608 * 15 = 125829120\ bits\\\\`

So,

Total Number of bits
`= 125829120 \ bits`

Now

The transmission rate of the total link= 49.7 Gbps

`1\ Gbps = 1000000000\ bps\\\\49.7 \ Gbps = 49.7 * 1000000000 =49700000000\ bps\\\\FDM \ \ network`

`\text{Calculating the transmission rate for 1 time slot:}`

`=( 49700000000)/(7) \ bits / second\\\\= 7100000000 \ bits / second\\\\ = (49700000000)/((10^(3* 7))) \ in\ milliseconds\\\\ =7100000 \ bits / millisecond`

Now,

`\text{Total time taken to transmit 15 MiB of file} = \frac{\text{Total number of bits}}{\text{Transmission rate}}`

`= (125829120)/(7100000)\\\\= 17.72\\\\`

`\text{Total time = Setup time + Transmission Time}\\\\`

`= 84.5+ 17.72\\\\= 102.2 \ milliseconds`