Question

Using the boh model of a He ion, what transition is most likelu to result in the emission of radiation with a wavelength of approximately 274 nm

Answer 1

`n=6\ to\ n=3`

Step-by-step explanation:

From the question we are told that:

Wavelength
`\lambda=274 *10^(-9)m`

Bohr's constant
`R = 1.097 × 10^7 / m (or m−1)`

Helium atom
`z=2`

Generally the equation for Wavelength is mathematically given by

`(1)/(\lambda)=Rz^2((1)/(nf^2)-(1)/(nf^2))`

`0.083=((1)/(nf^2)-(1)/(nf^2))`

Therefore

The Range of n fall at

`n=6\ to\ n=3`