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If mass of an empty 9.4 mL pycnometer is 10.3 and the mass of the same pycnometer with an unknown liquid is 20.1. Determine the density of the unknown liquid to the correct number of significant figures in g/mL

2 Answers

3 votes

Final answer:

The density of the unknown liquid is 1.043 g/mL.

Step-by-step explanation:

The density of a substance can be calculated using the formula:

Density (g/mL) = Mass (g) / Volume (mL)

In this case, the mass of the empty pycnometer is 10.3 g, and the mass of the pycnometer with the unknown liquid is 20.1 g. The volume of the pycnometer is given as 9.4 mL.

Using the formula, we can calculate the density:

Density = (Mass of pycnometer with liquid - Mass of empty pycnometer) / Volume of pycnometer

Density = (20.1 g - 10.3 g) / 9.4 mL

Density = 9.8 g / 9.4 mL

Density = 1.043 g/mL (rounded to 3 significant figures)

User Montserrat
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3.1k points
5 votes

Answer:

1.04 g/mL

Step-by-step explanation:

Applying,

D = (m-m')/V................. Equation 1

Where D = Density of the unknown liquid, m = mass of the pycnometer when filled with unkwon liquid, m' = mass of the empty pycnometer, V = volume of the empty pycnometer

From the question,

Assuming the mass are in grams

Given: m = 20.1 g, m' = 10.3 g, V = 9.4 mL

Substitute these values into equation 1

D = (20.1-10.3)/9.4

D = 9.8/9.4

D = 1.04 g/mL

User Kkawabat
by
3.6k points