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Neeedddd answweerrrr plaeeessee

Neeedddd answweerrrr plaeeessee-example-1

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Answer:

B. log_b(a) - log_b(d)

Explanation:

The applicable rule of logarithms is ...

log(a/b) = log(a) -log(b)

All the logs need to have the same base.

__

Here, the base is 'b', but the rule still applies:


\log_b{(a)/(d)}=\log_b{(a)}-\log_b{(d)}

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