Question

1) Find the measure of 0. (imagine that is an x) 2) Then, find the measure of AB. (the length from A to B) ​

Answer 1

θ ≈ 50°, AB ≈ 15.6

Explanation:

Using the tangent ratio in the right triangle

tanθ =
`(opposite)/(adjacent)` =
`(BC)/(AC)` =
`(11.9)/(10)` = 1.19 , then

θ =
`tan^(-1)` (1.19 ) ≈ 50° ( to the nearest degree

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Using the cosine ratio in the right triangle

cos50° =
`(adjacent)/(hypotenuse)` =
`(AC)/(AB)` =
`(10)/(AB)` ( multiply both sides by AB )

AB × cos50° = 10 ( divide both sides by cos50° )

AB =
`(10)/(cos50)` ≈ 15.6 ( to 1 dec. place )