Question

A boy im50kg at rest on a skateboard is pushed by another boy who exerts a force of 200 N on him. If the first boy's

final velocity is 8 m/s, what was the contact time?
seconds

Answer 1

Time, t = 2 seconds

Step-by-step explanation:

Given the following data;

Mass, m = 50 kg

Initial velocity, u = 0 m/s (since it's starting from rest).

Final velocity, v = 8 m/s

Force, F = 200 N

To find the time, we would use the following formula;

`F = \frac {m(v - u)}{t}`

Making time, t the subject of formula, we have;

`t = \frac {m(v - u)}{F}`

Substituting into the formula, we have;

`t = \frac {50(8 - 0)}{200}`

`t = \frac {50*(8)}{200}`

`t = \frac {400}{200}`

Time, t = 2 seconds