Question

Find the missing part.

Answer 1

`y=(15√(3))/(4)`

Explanation:

We are given that

`\theta_1=60^(\circ)`

`\theta_2=30^(\circ)`

We have to find the missing part.

`(x)/(15)=cos\theta_1=cos60^(\circ)`

Using the formula

`(base)/(hypotenuse)=cos\theta`

`x=15cos60^(\circ)=(15)/(2)`

`(z)/(15)=sin60^(\circ)`

Using the formula

`(Perpendicular\;arm)/(hypotenuse)=sin\theta`

`z=15* (√(3))/(2)=(15√(3))/(2)`

Now,

`(a)/(x)=cos60^(\circ)`

`(a)/((15)/(2))=(1)/(2)`

`a=(1)/(2)* 15/2=(15)/(4)`

`y=x sin60^(\circ)`

`y=(15)/(2)* (√(3))/(2)`

`y=(15√(3))/(4)`