Question

Find the points of intersection of the graphs involving the following pair of functions.

f(x)=2x^2 + 3x - 3 and g(x) = -x^2

Answer 1

The point of intersection is
`( (-1\pm√(5))/(2), 0)`

Explanation:

f(x) = 2x^2 + 3x - 3 and g(x) = - x^2

By equating them

2x^2 + 3x - 3 = -x^2

3x^2 + 3 x - 3 = 0

x^2 + x - 1 = 0

`x^2 +x - 1 = 0 \\\\x = (-1\pm√(5))/(2)`