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Slope intercept form

User MOntu
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1 Answer

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19 votes


(\stackrel{x_1}{4}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{4}}}\implies \cfrac{3}{-4}\implies -\cfrac{3}{4}


\begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-\cfrac{3}{4}}(x-\stackrel{x_1}{4}) \\\\\\ y-5=-\cfrac{3}{4}x+3\implies y=-\cfrac{3}{4}x+8

User Jesse Smith
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