Question

three condensers are connected in series across a 150 volt supply, the voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10^-8 c.calculate (a) the capacitance of each condenser (b)the effective capacitance of the combination

Answer 1

(a) 1.5 nF, 1.2 nF, 1 nF

(b) 0.4 nF

Step-by-step explanation:

V = 150 V

V' = 40 V, V'' = 50 V, V''' = 60 V, q = 6 x 10^-8 C

(a) C' = q/V' = 6 x 10^-8 / 40 = 1.5 x 10^-9 F

C'' = q/V'' = 6 x 10^-8 / 50 = 1.2 x 10^-9 F

C''' = q/V''' = 6 x 10^-8 / 60 = 1 x 10^-9 F

(b) The effective capacitance is

`(1)/(C)=(1)/(C')+(1)/(C'')+(1)/(C''')\\\\(1)/(C)=(10^9)/(1.5)+(10^9)/(1.2)+(10^9)/(1)\\\\C = 0.4* 10^(-9) F`