Question

PLESE HELp ANYONE. SOLVE ABC. ROUND YOUR ANSWERS TO THE NEAREST HUNDREDTH IF NECESSARY

Answer 1

C=25°

a=11

b=12

Explanation:

Find angle c,since angles in a triangle add up to 180 and we know angleA andB angle C will be

65+90+C=180

C=180-155

C=25°

To find a

use trig ratios

tanA=opposite/adjacent

tan65=a/5

a=tan65×5

a=10.72 round off to 11

To find b

sinC=opposite/hypotenuse

sin25=5/b

sin25 b=5

b=11.8 or rather 12

Answer 2

Explanation:

First find side a and to find this calculate tan 65

Tan 65 =
`(opposite \ side)/(adjacent\ side)=(a)/(5)\\\\`

2.144 = a/5

a = 2.144 * 5

b² = a² + c²

= 121+25

= 146.

b = √146 = 12.08 = 12

a = 10.72 = 11

Now find Tan C

`Tan \ C = (5)/(10.72)\\\\Tan \ C = 0.4664\\`

C = tan⁻¹ 0.4664

C = 25°