Question

A bus started from Kathmandu and reached khanikhola,26km far from Kathmandu, in one hour. if the bus had uniform acceleration, calculate the final velocity of the bus and acceleration. ​

Answer 1

a = 0.0040 m/s², v = 14.4 m/s.

Explanation:

Given that,

The distance between Kathmandu and Khanikhola, d = 26 km = 26000 m

Time, t = 1 hour = 3600 seconds

Let a is the acceleration of the bus. Using second equation of motion,

`d=ut+(1)/(2)at^2`

Where

u is the initial speed of the bus, u = 0

So,

`d=(1)/(2)at^2\\\\a=(2d)/(t^2)\\\\a=(2* 26000)/((3600)^2)\\\\a=0.0040\ m/s^2`

Now using first equation of motion.

Final velocity, v = u +at

So,

v = 0+0.0040(3600)

v = 14.4 m/s

Hence, this is the required solution.